Question #29971

if a(cap) and b(cap)are unit vectors at an angle theta show that |a(cap)-b(cap)=2(sin theta/2 )

Expert's answer

if a(cap) and b(cap) are unit vectors at an angle theta show that a(cap)b(cap)=2|a(\text{cap}) - b(\text{cap})| = 2 (sin theta/2)

a\vec{a} and b\vec{b} - are unit vectors

θ\theta - the angle between them



Law of cosines:

ab2=a2+b22abcosθ,\left|\vec{a} -\vec{b}\right|^2 = |\vec{a} |^2 +\left|\vec{b}\right|^2 -2|\vec{a} |\left|\vec{b}\right|\cos \theta ,

a,b\vec{a}, \vec{b} - some vectors, θ\theta - the angle between them

a\vec{a} and b\vec{b} - are unit vectors, therefore a=b=1|\vec{a}| = |\vec{b}| = 1

Law of cosines:

ab2=1+12cosθ=2(1cosθ)=1cosθ2=sinθ2=4sin2θ2\left|\vec{a} -\vec{b}\right|^2 = 1 + 1 - 2\cos \theta = 2(1 - \cos \theta) = \left|\sqrt{\frac{1 - \cos\theta}{2}} = \sin \frac{\theta}{2}\right| = 4\sin^2\frac{\theta}{2}

Or:

ab=2sinθ2\left|\vec{a} -\vec{b}\right| = 2\sin \frac{\theta}{2}

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