Question

A clock showing correct time when at a rest loses 1 hour when it is moving.what is velocity

Answer 1

Given:

$\Delta t=24\rm \: hr$

$\Delta \tau=23\rm \: hr$

The time delay equation says

$$\Delta t=\frac{\Delta \tau}{\sqrt{1-v^2/c^2}}$$

So, the required velocity

$$v=c\sqrt{1-(\Delta \tau/\Delta t)^2}$$

$$v=c\sqrt{1-(23/24)^2}=0.29c$$