Question #296969

 A fluid flow is given by : V = x * y ^ 2 * i - 2y * z ^ 2 * j - (z * y ^ 2 - (2z ^ 3)/3) * k. Prove that it is a case of possible steady incompressible fluid flow Calculate the velocity and acceleration at the point [1, 2, 3] .


1
Expert's answer
2022-02-13T12:15:36-0500

v=xy2i2yz2j(zy22z33)k,\vec v=xy^2\vec i-2yz^2\vec j-(zy^2-\frac{2z^3}3)\vec k,

v(1,2,3)=4i36j+6k,\vec v(1,2,3)=4\vec i-36\vec j+6\vec k,

a=y2i2z2j(y22z2)k,\vec a=y^2\vec i-2z^2\vec j-(y^2-2z^2)\vec k,

a(1,2,3)=4i18j+14k.\vec a(1,2,3)=4\vec i-18\vec j+14\vec k.


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