Question #296768

 a) State Snell’s law in equation form.                                                          

 

b) Light crosses from air to water. The angle of incidence is 750. Draw a schematic diagram of this

event.                                     

 c) Calculate the angle of refraction for the event in part b). Take the refractive index of water to be 4/3.   


1
Expert's answer
2022-02-14T13:41:43-0500

a). sin(α)sin(β=n2n1\frac{sin(\alpha)}{sin(\beta}=\frac{n_2}{n_1}


b).

α=750\alpha=75^0

n1=1n_1=1

n2=43n_2=\frac{4}{3}

then from the law Snellulus write down

sin(β)=n1n2sin(α)\sin(\beta)=\frac{n_1}{n_2}\sin(\alpha)

sin(β)=14/3sin(750)=340.966=0.724\sin(\beta)=\frac{1}{4/3}\cdot\sin(75^0)=\frac{3}{4}\cdot0.966=0.724

Then the refractive angle is equal

β=arcsin(0.724)=46.420\beta=\arcsin(0.724)=46.42^0



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