The rest mass of an electron is 9.1 x
10^-31 kg. What is the relativistic mass if its velocity is 55 % of the speed
of light?
Explanation & Calculation
Mrelativistic=mrest1−v2c2\qquad\qquad \begin{aligned} \small M_{relativistic}&=\small \frac{m_{rest}}{\sqrt{1-\large\frac{v^2}{c^2}}} \end{aligned}Mrelativistic=1−c2v2mrest
v=55100c ⟹ v2c2=5521002\qquad\qquad \begin{aligned} \small v&=\small \frac{55}{100}c\\ \implies \small \frac{v^2}{c^2}&=\small\frac{55^2}{100^2} \end{aligned}v⟹c2v2=10055c=1002552
Mr=9.1×10−31 kg1−5521002=1.1×10−30 kg⋯(increased)\qquad\qquad \begin{aligned} \small M_r&=\small \frac{9.1\times10^{-31}\,kg}{\sqrt{1-\frac{55^2}{100^2}}}\\ &=\small 1.1\times10^{-30}\,kg\cdots(\text{increased}) \end{aligned}Mr=1−10025529.1×10−31kg=1.1×10−30kg⋯(increased)
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