Safawi kicked a ball with an initial speed of 20 ms-1 at 30o angle. If the ball experienced a constant vertical acceleration of -9.81 ms-2, calculate the ball’s maximum height and distance.
h=v2sin2α2g=5.1 m,h=\frac{v^2\sin^2\alpha}{2g}=5.1~m,h=2gv2sin2α=5.1 m,
l=v2sin2αg=35.3 m.l=\frac{v^2\sin2\alpha}g=35.3~m.l=gv2sin2α=35.3 m.
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