2. Compute the contracted length of an
object whose initial length 30 m and travel with a velocity 0.65c?
Solution
initial length L=30 m
velocity v=0.65c
contracted length of an
object
L′=L1−v2c2L'=L\sqrt{1-\frac{v^2}{c^2}}L′=L1−c2v2
Putting all values
L′=30×1−(0.65c)2c2=30×0.5775=22.8mL'=30\times\sqrt{1-\frac{(0.65c)^2}{c^2}}\\=30\times\sqrt{0.5775}\\=22.8mL′=30×1−c2(0.65c)2=30×0.5775=22.8m
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