A cantilever of length 2 m carries two point loads of 20 KN at the free end and 30 KN at a distance of 1 m from the free end. Find the slope and deflection at free end. Take E= 2×10^5 N/mm^2 and I= 1.5×10^8 mm^4
Given quantities:
l=2ml = 2ml=2m
E=2∗105Nmm2E=2*10^5 \frac{N}{mm^2}E=2∗105mm2N
I=1.6∗108mm4I=1.6*10^8 mm^4I=1.6∗108mm4
θ−?\theta-?θ−?
θ=wl22EI=20∗222∗12∗102=0.0033rad\theta = \frac{wl^2}{2EI}=\frac{20*2^2}{2*12*10^2}=0.0033radθ=2EIwl2=2∗12∗10220∗22=0.0033rad
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