Answer to Question #292343 in Mechanics | Relativity for Sandeep yadav

Question

Solve the following ordinary differential equations:

a) 3d²y/dx²+dy/dx-14y=0 ; y(0)=1 , y'(0)=1

Answer 1

Explanations & Calculations

• The answer of this ordinary differential equation is as follows.

$\qquad\qquad \begin{aligned} \small y(x)&=\small 39e^{-\frac{x}{3}}+14x-38 \end{aligned}$