Question #291845

a child of mass 40 kg slides down a water slide that is 15 m high. at the bottom her velocity is 9.7 m/s. approximately how much energy was "lost" due to friction?


1
Expert's answer
2022-01-30T13:51:57-0500

Solution

Mass of child m=40kg

Height h=15m

Velocity at bottom

v=9.7m/s

So energy at height h

U=mgh

=40×9.81×1540\times9.81\times15

=5886J=5886J

Energy at bottom

E=0.5mv20.5mv^2

=0.5×40×(9.7)2=1881.8J=0.5\times40\times(9.7) ^2\\=1881.8J

Loss of energy due to friction

=UE=58861881.8=4004.2J=U-E\\=5886-1881.8\\=4004.2J


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