an object of mass 60 kg is raised 12 m and then released. assuming no losses due to air resistance, what is its velocity two-thirds of the way down?
Answer
Mass of object m=60kg
Raised at height h=12m
So potential energy
U=mgh
Potential energy at height h'=8m(two-thirds)
Let kinetic energy is E at this height
Now using energy conservation
So velocity of object
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