Question

What force must be exerted on the master cylinder of a hydraulic lift to support the weight of a 2 500 kg car a large car resting on the slave cylinder? The master cylinder has a 4.00 cm diameter and the slave has a 25.0 cm diameter.

Answer 1

Gives

$m_2=2500kg$

$r_1=0.02m$

$r_2=\frac{25\times10^{-2}}{2}$ =0.125m

$P_1=P_2$

$\frac{F_1}{A_1}=\frac{F_2}{A_2}$

$F_1=\frac{A_1}{A_2}\times F_2$

$F_1=\frac{r_1^2}{r_2^2}\times F_2$

$$F_1=\frac{0.02^2}{0.125^2}\times2500\times9.8=627.2N$$