The mass m1 of one of the small spheres of a cavendish balance is 0.01kg,the mass m2 of the nearest large sphere is 0.50kg and the centre to centre distance between them is 0.05m.find the gravitational force on each sphere due to other.
Explanations & Calculations
F=G.m1.m2r2=6.67×10−11Nkg−2m2.[0.01 kg×0.50 kg(0.05 m)2]=6.67×10−11×[2] N=1.33×10−11 N\qquad\qquad \begin{aligned} \small F&=\small G.\frac{m_1.m_2}{r^2}\\ &=\small 6.67\times10^{-11}Nkg^{-2}m^2.\Bigg[\frac{0.01\,kg\times0.50\,kg}{(0.05\,m)^2}\Bigg]\\ &=\small 6.67\times10^{-11}\times\big[2\big]\,N\\ &=\small 1.33\times10^{-11}\,N \end{aligned}F=G.r2m1.m2=6.67×10−11Nkg−2m2.[(0.05m)20.01kg×0.50kg]=6.67×10−11×[2]N=1.33×10−11N
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