Question

A boulder of mass 100 kg is pulled in some direction with a net force whose components are

A.

B.

C.

D.

= 100 N, 𝐹 = 200 N.

Answer 1

Explanation & Calculations

• Here it sounds like it asks for the net force.
• Normally, the components are taken orthogonal to each other. $\small 100\,N\,\angle{90^\circ}\,200\,N$.
• Then, using the Pythagorean theorem, the resultant can be calculated as follows.

$\qquad\qquad \begin{aligned} \small R&=\small \sqrt{100^2+200^2}\\ &=\small 223.6\,N \end{aligned}$

• The angle created with the $\small 200\,N$ can be calculated as $\small \tan\theta=\frac{100\,N}{200\,N}$ .
• However, it is impossible to provide a precise answer without seeing the 4 options.