Evaluate the moment of inertia of a thin rod with axis of rotation at the centre, if its length is 100cm and its mass is 2.3kg
The moment of inertia for a thin rod of mass m and length L can be calculated as follows:
I=112mL2=166.7 kgโ m2.I=\dfrac1{12}mL^2=166.7\text{ kg}ยท\text m^2.I=121โmL2=166.7 kgโ m2.
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