A 2.96 kg particle has a velocity of (3.00 i hat - 4.06 j) m/s.
(a) Find its x and y components of momentum.
Let the velocity vector be:
v=(3,4) m/s\mathbf{v} = (3, 4)\space m/sv=(3,4) m/s
By definition, the momentum is:
p=mv=2.96⋅(3,4)=(7.88,11.84)kg⋅m/sp=mv=2.96⋅(3,4)=(7.88,11.84) kg⋅m/sp=mv=2.96⋅(3,4)=(7.88,11.84)kg⋅m/s
X components= 7.88kg⋅m/s7.88kg⋅m/s7.88kg⋅m/s
Y components =11.84kg⋅m/s11.84kg⋅m/s11.84kg⋅m/s
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments