A 100N weight rest on a 30 degrees inclined plane. Neglecting friction, how much pull must one exert to bring the weight up the plane
Component of gravity acting along an inclined plane:\text{Component of gravity acting along an inclined plane:}Component of gravity acting along an inclined plane:
Fg=mgsinαF_g = mg\sin\alphaFg=mgsinα
α=30°\alpha= 30\degreeα=30°
mg=100Nmg = 100Nmg=100N
Fmin=FgF_{min} = F_gFmin=Fg
Fmin=100sin30°=50NF_{min} = 100\sin30\degree= 50NFmin=100sin30°=50N
Answer:50N\text{Answer:} 50NAnswer:50N
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