Explanation & Calculation
- All the quantities are given in vector form so that it is just the addition of the coefficients of each unit vector to get the sum of them.
Σ=3i+4j−5k+(−i+2j+6k)=(3−1)i+(4+2)j+(−5+6)k=2i+6j+k
- There should be a mistake in the second vector with its last unit vector. Unless the z is defined there is no meaning to the question.
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