Question #287309

Derive the momentum of inertia component of a rotating rigid body

1
Expert's answer
2022-01-14T09:48:14-0500

Assume we have a point mass m rotating at distance r from the axis of rotation at speed v. Then, by definition, the moment of inertia is


I=Lω=[mvr][v/r]=mr2.I=\dfrac L\omega=\dfrac {[mv·r]}{[v/r]}=mr^2.


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