Question #286868

A roller coaster starts at 2.5m/s at a height of 25m above the ground. Determine the speed of the roller coaster when it is:

a. 20m above the ground;

b. 10m above the ground;

c. At ground level.


1
Expert's answer
2022-01-13T09:39:01-0500

Answer

Initial speed

u=2.5 m/sec

Height H=25m

The initial kinetic energy of roller coaster

KEi=mu22KE_i=\frac{mu^2}{2}

Final kinetic energy

KEf=mv22KE_f=\frac{mv^2}{2}

a) using energy conservation

mg(H-h) =mv22mu22\frac{mv^2}{2}-\frac{mu^2}{2}

So speed of roller caster at 20m

v=u2+2g(Hh)=25×25+2×9.8×5=26.89m/sv=\sqrt{u^2+2g(H-h)}\\=\sqrt{25\times25+2\times9.8\times5}\\=26.89m/s

b) at height h=10m

So speed

v=u2+2g(Hh)=25×25+2×9.8×15=30.31m/sv=\sqrt{u^2+2g(H-h)}\\=\sqrt{25\times25+2\times9.8\times15}\\=30.31m/s

c) at ground level

v=u2+2gH=25×25+2×9.8×25=33.39m/sv=\sqrt{u^2+2gH}\\=\sqrt{25\times25+2\times9.8\times25}\\=33.39m/s


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