Question #28672

a body starting from rest travels with uniform acceleration. if it ravels 100 m in 5 seconds what is the value of acceleration?

Expert's answer

A body starting from rest travels with uniform acceleration. If it travels 100 m in 5 seconds what is the value of acceleration?

Solution.

The distance traveled by the body after tt seconds with uniform acceleration am/s2a \, \text{m/s}^2 is:


S=v0t+12at2m;S = v_0 t + \frac{1}{2} a t^2 \, \text{m};


where v0(m/s)v_0 \, (\text{m/s}) is the initial velocity of the body;

In this case v0=0v_0 = 0, because body is starting to travel from rest. So:


S=12at2;S = \frac{1}{2} a t^2;


Find the acceleration:


a=2St2=2×10052=8m/s2;a = \frac{2S}{t^2} = \frac{2 \times 100}{5^2} = 8 \, \text{m/s}^2;


Answer: the acceleration is 8m/s28 \, \text{m/s}^2.

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