Question #286032

Four identical masses of 2 kg each are situated at the four corner of the square. A side of the square measures 3.0m. Find the moment of inertia about an axis passing through the center of the square and perpendicular to its plane


Expert's answer

Explanations & Calculations


  • It is the sum of M.O.Is of each mass around the axis.

I=Σmr2=(322m)2[2kg+2kg+2kg+2kg]=36kgm2\qquad\qquad \begin{aligned} \small I&=\small \Sigma mr^2\\ &=\small (\sqrt{\frac{3\sqrt2}{2}\,m})^2\Big[2\,kg+2\,kg+2\,kg+2\,kg\Big]\\ &=\small 36\,kgm^2 \end{aligned}


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