. a force of 100N is applied to the rim of the pulley wheel of diameter 200mm. Solve for the torque.
M=Fl=Fd2,M=Fl=F\frac d2,M=Fl=F2d,
M=100⋅0.22=10 N⋅m.M=100\cdot\frac{0.2}2=10~~\text N\cdot\text m.M=100⋅20.2=10 N⋅m.
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments