Explanations & Calculations
- The ball falls under gravity which is almost constant for the low heights above earth.
- Hence you can use any of the 4 motion equations suitably to find the unknown value.
- You are given the initial velocity, height at which the ball was released, and asked for the time it takes to reach the ground.
- The hidden quantity/ directly not given but you need to know is the gravitational acceleration g=9.8ms−2 .
- Then you can use s=ut+21at2 downwards from the starting point to find the time. (then the downward direction is +, all the vector quantities direct downward are taken + while any others upwards are taken negative) )
+30.9m0t=+7.95ms−1×t+21×(+9.8)×t2=4.9t2+7.95t−30.9⋯[a quadratic function]={1.83s−3.45s⋯[neglected]
- Then the time it would take is 1.83s
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