Question

The coordinates of a particles in meters per second is given by v(t)=12t-3t where the time (this in second at what value of (1) will the particles becomes momentarily at rest?

Answer 1

$v(t)=12t-3t^2$

The particle becomes momentarily at rest when velocity becomes zero.

So,$v(t)=12t-3t^2=0$

$\implies 3t(4-t)=0$

$\implies t=0,4$

Ignoring $t=0,$

After $4$ seconds ,the particle comes momentarily at rest.