What must be the velocity of a spacecraft if 1 ℎ on its clock is to correspond to 1 ℎ + 1 𝑠 on a clock on
the earth?
Explanation & Calculation
"\\qquad\\qquad\n\\begin{aligned}\n\\small T&=\\small \\frac{T'}{\\sqrt{1-\\large\\frac{v^2}{c^2}}}\\\\\n\\small 3601\\,s&=\\small \\frac{3600\\,s}{\\sqrt{1-\\large\\frac{v^2}{c^2}}}\\\\\n\\small v&=\\small 0.0236c\n\\end{aligned}"
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