What must be the velocity of a spacecraft if 1 ℎ on its clock is to correspond to 1 ℎ + 1 𝑠 on a clock on
the earth?
Explanation & Calculation
T=T′1−v2c23601 s=3600 s1−v2c2v=0.0236c\qquad\qquad \begin{aligned} \small T&=\small \frac{T'}{\sqrt{1-\large\frac{v^2}{c^2}}}\\ \small 3601\,s&=\small \frac{3600\,s}{\sqrt{1-\large\frac{v^2}{c^2}}}\\ \small v&=\small 0.0236c \end{aligned}T3601sv=1−c2v2T′=1−c2v23600s=0.0236c
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