Question

A patient transport vehicle is running at a speed of 80 m/s. It is the decelerated at the rate of 10m/s. When will it stop?

Answer 1

acceleration:

$a=\frac{v_2-v_1}{t}$

we have:

$a=-10$ m/s²

$v_2=0$

$v_1=80$ m/s

vehicle will stop after:

$t=\frac{v_2-v_1}{a}=\frac{80}{10}=8$ s