Explanations & Calculations
- For this, you need to use the formula for intensity at a given point from the source.
- You can use it separately for the given 2 situations and find the intensity in the second situation.
III5×10−6I15×10−6I1=AP=4πr2P≈r21≈421⋯(1)≈221⋯(2)=2242
- Once you subject I1 , you get the answer.
Comments