Answer to Question #282078 in Mechanics | Relativity for Lee

Question #282078

Is the equation v = v0 + ax dimensionally correct?


1
Expert's answer
2021-12-22T14:08:16-0500

v=v0+axv =v_0+a*x

Dimension:\text{Dimension:}

v[LT]v- [\frac{L}{T}]

v0[LT]v_0- [\frac{L}{T}]

a[LT2]a- [\frac{L}{T^2}]

x[L]x -[L]

[LT][LT]+[L2T2][\frac{L}{T}]\not =[\frac{L}{T}]+[\frac{L^2}{T^2}]

11+[LT]1\not =1+[\frac{L}{T}]


Answer: equation is not dimensionally correct\text{Answer: equation is not dimensionally correct}


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment