Question #281913

secutive standing waves occur at frequencies 280 Hz and 315 Hz on a taut

g fixed at both ends. Determine the frequency of the 4th harmonic.


1
Expert's answer
2021-12-22T14:10:11-0500

Explanations & Calculations


  • The frequency of nth\small n^{th} harmonic is given by,

fn=nv2L\qquad\qquad \begin{aligned} \small f_n&=\small \frac{nv}{2L} \end{aligned}

  • Then, for the consecutive frequencies: n&(n+1)\small n\,\&\,(n+1), since this arrangement allows for ll harmonics n=1,2,3,...\small n =1,2,3,...

280=nv2L315=(n+1)v2L=nv2L+v2L=280+v2Lv2L=35\qquad\qquad \begin{aligned} \small 280&=\small \frac{nv}{2L}\\\\ \small 315&=\small \frac{(n+1)v}{2L}\\ &=\small \frac{nv}{2L}+\frac{v}{2L}\\ &=\small 280+\frac{v}{2L}\\ \small \frac{v}{2L}&=\small 35 \end{aligned}

  • Now for the fourth harmonic for which n=4\small n=4, you can calculate the quantity: 4.v2L\large\frac{4.v}{2L}.

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