Answer to Question #281211 in Mechanics | Relativity for BxJ

Mechanics | Relativity

Question #281211

A stone is dropped from the top of a tower hits the ground 6 seconds later. How high is the tower?

Expert's answer

g = 9.8 m/s²

V₀ = 0

"h=V_0t+\\frac{1}{2}gt^2=0+\\frac{1}{2}\u00d79.8\\frac{m}{s^2}\u00d7(6s)^2=176.4\\ m"

Answer: 176.4 m

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