If oil flows out of a pipe at the speed of 2.65m/s and the diameter of the pipe is 5.0cm, determine the discharge rate?
radius of the pipe=5/2=2.5cm=0.025m5/2=2.5cm=0.025m5/2=2.5cm=0.025m
cross-section area of the pipe=πr2=3.142×0.0252=0.001964m2=\pi r^2=3.142\times 0.025^2 =0.001964m^2=πr2=3.142×0.0252=0.001964m2
discharge rate=speed of flow ×\times× cross-section area=2.65×0.001964=0.005205m3/s2.65\times 0.001964=0.005205m^3/s2.65×0.001964=0.005205m3/s
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