A harmonic oscillator vibrates with frequency of 4 HZ and an amplitude of 2cm.what is its maximum velocity?
Vmax=Aωω=2πf=8π rad/sA=2 cm=0.02 mVmax=0.02×8π=0.5 m/s=16 π cm/sV_{max} = Aω \\ ω = 2 \pi f = 8 \pi \;rad/s \\ A = 2 \;cm = 0.02 \; m\\ V_{max} = 0.02 \times 8 \pi = 0.5 \;m/s = 16 \; \pi \; cm/sVmax=Aωω=2πf=8πrad/sA=2cm=0.02mVmax=0.02×8π=0.5m/s=16πcm/s
Need a fast expert's response?
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!
Comments