Question #280646

At the instant a harmonic oscillator has a displacement of -8cm,its acceleration is 2cm/s,what is the period

1
Expert's answer
2021-12-17T14:00:38-0500

Explanations & Calculations


  • For this, you need to consider the characteristic equation of the harmonic motion.
  • The displacement is measured to be negative and the acceleration to be positive.

a=ω2x=(2πT)2.x2cms1=(2πT).(8cm)\qquad\qquad \begin{aligned} \small a&=\small -\omega^2x\\ &=\small -\Big(\frac{2\pi}{T}\Big)^2.x\\ \small 2\,cms^{-1}&=\small -\Big(\frac{2\pi}{T}\Big).(-8\,cm)\\ \end{aligned}

  • You can now give it a try to subject the period: T.

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