Question

calculate the wavelength of water waves which, on passing throug a gap 50cm wid, create a diffraction pattern such that the angle between the center of the pattern and the second-order minimum is 60°

Answer 1

calculate the wavelength of water waves which, on passing through a gap 50cm width, create a diffraction pattern such that the angle between the center of the pattern and the second-order minimum is 60°

Solution

We use the formula

$$d \sin \theta = n \lambda$$

where $d$ is the gap size; $\theta$ is the angle; $n$ is the order number; $\lambda$ is the wavelength.

So

$$\lambda = \frac{d \sin \theta}{n} = \frac{0.5 * \sin 60}{2} = 0.2165 \, \text{m}$$

Answer: 0.2165m.