A stone is thrown upward and reaches a height of 19.6 meters. With what initial velocity was it thrown?
mgh=mV22mgh=\frac{mV^2}{2}mgh=2mV2
V=2gh=2×9.8×19.6=19.6m/sV=\sqrt{2gh}=\sqrt{2\times 9.8 \times 19.6}=19.6m/sV=2gh=2×9.8×19.6=19.6m/s
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