Answer to Question #280244 in Mechanics | Relativity for BxJ

Question #280244

A stone is thrown upward and reaches a height of 19.6 meters. With what initial velocity was it thrown?

1
Expert's answer
2021-12-16T11:32:07-0500

mgh=mV22mgh=\frac{mV^2}{2}

V=2gh=2×9.8×19.6=19.6m/sV=\sqrt{2gh}=\sqrt{2\times 9.8 \times 19.6}=19.6m/s


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