Answer to Question #280244 in Mechanics | Relativity for BxJ

Question

A stone is thrown upward and reaches a height of 19.6 meters. With what initial velocity was it thrown?

Answer 1

$mgh=\frac{mV^2}{2}$

$V=\sqrt{2gh}=\sqrt{2\times 9.8 \times 19.6}=19.6m/s$