Answer to Question #280237 in Mechanics | Relativity for BxJ

Question

A truck driver is driving at a velocity of 60 km/h. He sees a danger ahead and steps on his brakes. He stop the truck in exactly 5 seconds. How far does he go before coming to a stop?

Answer 1

$v_0 = 60\frac{km}{h}=\frac{60*1000}{3600}\approx16.7\frac{m}{s}$

$v_1 = 0$

$t = 5s$

$a = \frac{v_1-v_0}{t}= -3.34\frac{m}{s^2}$

$s = v_0t+\frac{at^2}{2}=16.7*5- \frac{3.34*25}{2}= 41.75m$

$\text{Answer: } 41.75m$