Question #280071

You attach a 2.50 kg block to a horizorsal spring that is fixed at one end. You pull the block until the spring is stretched by


0.400 m and release it from rest. Assume the block sides on a horizontal surface with negligible friction The block reaches a


speed of zero again 0.400 s after release (for the first time after release). What is the maximum speed of the block (in m/s)?

1
Expert's answer
2021-12-16T11:33:57-0500

vmax=Aωv_{max}=A\omega

ω=2π/T\omega=2\pi/T

we have:

T=20.4=0.8T=2\cdot 0.4=0.8 s

A=0.4A=0.4 m

then:

vmax=0.4π/0.4=3.14v_{max}=0.4\pi/0.4=3.14 m/s


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!
LATEST TUTORIALS
APPROVED BY CLIENTS