cocnsider the combination of two capacitors C1 and C2 with C2>C1 when connected in parallel , the equivalent capacitance is 8 times the equivalent capacitance of the same connected in series. calculate the ratio of capacitors, C2/C1.
"C_1+C_2=8\\frac{C_1C_2}{C_1+C_2}\\to(\\frac{C_2}{C_1})^2-6\\cdot(\\frac{C_2}{C_1})+1=0\\to"
"C_2\/C_1=5.83" . Answer
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