A 50-kg person stands 1.5 m away from one end of a uniform 6.0-m-long scaffold of mass 70.0 kg. Find the tensions in the two vertical ropes supporting the scaffold.
for sum of torques:
∑τa=0:1.5⋅50⋅9.8+3⋅70⋅9.8−6T2=0→T2=465.5 (N)\sum{\tau_a=0}:1.5\cdot50\cdot9.8+3\cdot70\cdot9.8-6T_2=0\to T_2=465.5\ (N)∑τa=0:1.5⋅50⋅9.8+3⋅70⋅9.8−6T2=0→T2=465.5 (N)
∑τb=0:3⋅70⋅9.8+4.5⋅50⋅9.8−6T1=0→T1=710.5 (N)\sum{\tau_b=0}:3\cdot70\cdot9.8+4.5\cdot50\cdot9.8-6T_1=0\to T_1=710.5\ (N)∑τb=0:3⋅70⋅9.8+4.5⋅50⋅9.8−6T1=0→T1=710.5 (N)
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