Answer to Question #279349 in Mechanics | Relativity for btch

Question

The mass of the meter stick is 150.0 g and the masses to the left of the fulcrum are m1=50.0gm1=50.0g and m2=75.0g.m2=75.0g. Find the mass m3m3 that balances

the system when it is attached at the right end of the stick, and the normal reaction force at the fulcrum when the system is balanced.

Answer 1

$30m_3+15\cdot 150\cdot \frac{30}{100}=70m_1+40m_2+35\cdot 150\cdot \frac{70}{100},$

$m_3=114~g,$

$T=\Sigma mg=3.8~N.$