Question #279334

Superman throws a 2400-N boulder at an adversary. What

horizontal force must Superman apply to the boulder to give it a

horizontal acceleration of 12.0 m/s2?


1
Expert's answer
2021-12-15T11:21:12-0500

P=240N    a=12ms2P = 240N \space\space\space\space a = 12\frac{m}{s^2}

F=ma=Pga=2401012=288NF = ma = \frac{P}{g}a=\frac{240}{10}*12=288N


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