Superman throws a 2400-N boulder at an adversary. What
horizontal force must Superman apply to the boulder to give it a
horizontal acceleration of 12.0 m/s2?
P=240N a=12ms2P = 240N \space\space\space\space a = 12\frac{m}{s^2}P=240N a=12s2m
F=ma=Pga=24010∗12=288NF = ma = \frac{P}{g}a=\frac{240}{10}*12=288NF=ma=gPa=10240∗12=288N
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