Answer to Question #279051 in Mechanics | Relativity for Nikko

Question #279051

How many particles are present in a closed container if the energy it contains is 95577.88J, and the diatomic oxygen gas is moving at a velocity of 51.28m/s?


1
Expert's answer
2021-12-13T10:34:20-0500

Solution:


Energy and number of particle relation is given by as

E=nMAv22NAE=\frac{nM_Av^2}{2N_A}

n=2ENAMAv2n=\frac{2E N_A}{M_Av^2}


n=2×95577.88×6.023×102332×(51.28)2n=\frac{2\times95577.88\times 6.023\times 10^{23}}{32\times(51.28)^2}


n=13.68×1023n=13.68\times10^{23}

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