If the person and the cricket ball consist of a system, find the position and velocity of the center of mass of the system at time t=0.5 s
The position of the center of mass after 0.5s can be calculated using the 2nd equation of motion.
"y=y_0+v_yt+\\frac{1}{2}gt^2"
"v_y=0"
g=9.8m/s
"y_0=11.5m"
t=0.5
"y=11.5+\\frac{1}{2}\u00d7(-9.8)\u00d70.5^2=10.275m"
Velocity of the center of mass after 0.5sec is calculated using the 1st equation of motion:
"v_y=u_y+at"
"u_g=0"
"v_y=-9.8\u00d70.5= -4.9ms^{-1}"
The negative sign signifies that the directions of motion
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