Question #275322

Respectfully, the answer provided to my question #274901 does not address the question I asked.

Can we say, from special relativity, that since the accelerating force was applied to object B, that the clock in B will, in reality, tick more slowly than the clock in A?

Please disregard the effects of gravity for this scenario.

Thank you.


Expert's answer

After compensating for varying signal delays due to the changing distance between an observer and a moving clock (i.e. Doppler effect), the observer will measure the moving clock is ticking slower than a clock that is at rest in the observer's own reference frame.

So, the clock in B will, in reality, tick more slowly than the clock in A.


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