Question #27520

A plane is flying with a constant speed along a straight line at an angle of 30° with the horizontal.
The weight of the plane is 80, 000 N and its engine provides a thrust of 100, 000 N in the
direction of flight. Two additional forces are exerted on the plane: the lift force perpendicular to
the plane’s wings, and the force due to air resistance opposite to the direction of motion. Draw
the free-body diagram showing all forces on the plane. Determine the lift force and the force due
to air resistance.

Expert's answer

A plane is flying with a constant speed along a straight line at an angle of 3030{}^{\circ} with the horizontal. The weight of the plane is 80,000 N and its engine provides a thrust of 100,000 N in the direction of flight. Two additional forces are exerted on the plane: the lift force perpendicular to the plane's wings, and the force due to air resistance opposite to the direction of motion. Draw the free-body diagram showing all forces on the plane. Determine the lift force and the force due to air resistance.

Solution

FF - lift force, RR - the force due to air resistance, TT - force provided by engine.

The lift force FF provided by the wings


F=Wcos30=80,000cos30=69,282N.F = W \cos 30 = 80,000 * \cos 30 = 69,282N.


As the plane has a constant speed the net force acting along the line of flight must be zero. Which means

T=T = weight component 'down the slope' +R+ R

100,000=(80,000sin30)+RR=100,00040,000=60,000N100,000 = (80,000 \cdot \sin 30) + R \rightarrow R = 100,000 - 40,000 = 60,000N


Answer: 69,282N; 60,000N.

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