Answer to Question #274702 in Mechanics | Relativity for Victor

Question

A stone of mass 0.5kg is thrown vertically upward with velocity of 10m/s.

Find the potential energy at its greatest hight (h).

The kinetic energy on reaching the ground again (assume g=10m/s and neglect air resistance

Answer 1

at greatest height v = 0

so,

potential energy at greatest height:

$mgh=mv_0^2/2=0.5\cdot10^2/2=25$ J

kinetic energy on reaching the ground again = potential energy at greatest height