Question #274702

A stone of mass 0.5kg is thrown vertically upward with velocity of 10m/s.



Find the potential energy at its greatest hight (h).



The kinetic energy on reaching the ground again (assume g=10m/s and neglect air resistance

1
Expert's answer
2021-12-02T13:58:31-0500

at greatest height v = 0

so,

potential energy at greatest height:

mgh=mv02/2=0.5102/2=25mgh=mv_0^2/2=0.5\cdot10^2/2=25 J


kinetic energy on reaching the ground again = potential energy at greatest height


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