If the sound intensity 4.0 m from a point sound source is 1.0 × 10-⁶ Wm², what will be the sound intensity at each of the following distances from the source:
A. 1.0 m? And
B. 2.0 m?
I(r)=P4πr2I(r) =\frac{P}{4\pi r^2}I(r)=4πr2P
I(4)=P64π=1.0×106Wm2I(4) = \frac{P}{64\pi }=1.0×10^6\frac{W}{m^2}I(4)=64πP=1.0×106m2W
I(1)=P4π=I(4)16=0.625×105Wm2I(1)= \frac{P}{4\pi }=\frac{I(4)}{16}=0.625×10^5\frac{W}{m^2}I(1)=4πP=16I(4)=0.625×105m2W
I(2)=P16π=I(4)4=0.25×106Wm2I(2)= \frac{P}{16\pi }=\frac{I(4)}{4}=0.25×10^6\frac{W}{m^2}I(2)=16πP=4I(4)=0.25×106m2W
Answer: \text{Answer: }Answer:
A. 0.625×105Wm2A.\ 0.625×10^5\frac{W}{m^2}A. 0.625×105m2W
B. 0.25×106Wm2B.\ 0.25×10^6\frac{W}{m^2}B. 0.25×106m2W
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