Answer to Question #271474 in Mechanics | Relativity for JINGJING

Question

A volleyball player hits the ball 40 cm above the top of the net towards his opponents’ court at a velocity of 15.0 m/s along the horizontal. If the top of the net is 2.0 m high from the floor and the length of the opponents’ court is 9.0 m, will the volleyball land within the opponents’ court? Why?

Answer 1

$h_0 = 2m$

$h_1= 40cm =0.4m$

$s_1 = 9m$

$v_0 = 15\frac{m}{s}$

$g = 9.8\frac{m}{s^2}$

$h = h_0+h_1 = 2.4m$

$\text{Ball movement time:}$

$t = \sqrt\frac{2h}{g}=\sqrt\frac{2*2.4}{9.8}\approx0.69s$

$s = v_0t= 15*0.69= 10.35m$

$s>s_1$

$\text{The distance traveled by the ball before falling is}$

$\text{greater than the length of the court}$

$\text{Answer: The ball will not hit the court}$