A body of mass 4kg moving with a velocity of 7m/s is acted upon by a force of 20N for 0.1s. Determine the final velocity of the body
Solution.
m=4kg;m=4 kg;m=4kg;
v0=7m/s;v_0=7 m/s;v0=7m/s;
F=20N;F=20N;F=20N;
t=0.1s;t=0.1 s;t=0.1s;
Ft=mv−mv0 ⟹ v=Ft+mv0m;Ft=mv-mv_0\implies v=\dfrac{Ft+mv_0}{m};Ft=mv−mv0⟹v=mFt+mv0;
v=20N⋅0.1s+4kg⋅7m/s4kg=7.5m/s;v=\dfrac{ 20N\sdot0.1s+4 kg\sdot 7 m/s}{4 kg}=7.5 m/s;v=4kg20N⋅0.1s+4kg⋅7m/s=7.5m/s;
Answer: v=7.5m/s.v=7.5 m/s.v=7.5m/s.
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