Answer to Question #271226 in Mechanics | Relativity for Bhumie

Question

A body of mass 4kg moving with a velocity of 7m/s is acted upon by a force of 20N for 0.1s. Determine the final velocity of the body

Answer 1

Solution.

$m=4 kg;$

$v_0=7 m/s;$

$F=20N;$

$t=0.1 s;$

$Ft=mv-mv_0\implies v=\dfrac{Ft+mv_0}{m};$

$v=\dfrac{ 20N\sdot0.1s+4 kg\sdot 7 m/s}{4 kg}=7.5 m/s;$

Answer: $v=7.5 m/s.$